Find the mass of potassium hydroxide obtained by reacting 188 g of potassium oxide with water.

Let’s implement the solution:

According to the condition of the problem, we write down the equation of the process:
m = 188 g Xg -?

K2O + H2O = 2KOH – compounds, obtained potassium hydroxide;

Calculations:
M (K2O) = 94.2 g / mol;

M (KOH) = 56.1 g / mol;

Y (K2O) = m / M = 188 / 94.2 = 1.99 = 2 mol.

Proportion:
2 mol (K2O) – X mol (KOH);

-1 mol -2 mol hence, X mol (KOH) = 2 * 2/1 = 4 mol.

4. Find the mass of the base:

m (KOH) = Y * M = 4 * 56.1 = 224.4 g

Answer: the mass of potassium hydroxide is 224.4 g