Find the mass of salt formed by the interaction of a solution of hydrochloric acid 15 g

Find the mass of salt formed by the interaction of a solution of hydrochloric acid 15 g of magnesium containing 20% impurities.

1. Let us write down the equation of the proceeding reaction:

Mg + 2HCl = MgCl2 + H2 ↑;

2.Calculate the mass of magnesium without impurities:

m (Mg) = w (Mg) * m (sample);

w (Mg) = 1 – w (impurities) = 1 – 0.2 = 0.8;

m (Mg) = 0.8 * 15 = 12 g;

3. find the chemical amount of magnesium:

n (Mg) = m (Mg): M (Mg) = 12: 24 = 0.5 mol;

4. Determine the amount and calculate the mass of the obtained magnesium chloride:

n (MgCl2) = n (Mg) = 0.5 mol;

m (MgCl2) = n (MgCl2) * M (MgCl2);

M (MgCl2) = 24 + 35.5 * 2 = 95 g / mol;

m (MgCl2) = 0.5 * 95 = 47.5 g.

Answer: 47.5 g.