Find the mass of salt obtained by reacting 6 g of acetic acid with an excess of sodium hydroxide.

To solve, we compose the equation of the process:

CH3COOH + NaOH = CH3COONa + H2O – ion exchange, sodium acetate salt was formed;
Calculations by formulas:
M (CH3COOH) = 60 g / mol;

M (CH3COONa) = 81.9 g / mol.

3. Determine the amount of acid:

Y (CH3COOH) = m / M = 6/60 = 0.1 mol;

Y (CH3COONa) = 0.1 mol since the amount of substances is 1 mol.

4. Find the mass of salt:

m (CH3COONa) = Y * M = 0.1 * 81.9 = 8.19 g

Answer: Received sodium acetate weighing 8.19 g