Find the mass of salt that forms when 2.7 grams of aluminum reacts with H2SO4.

Reaction equation: 2Al + 3H2SO4 = Al2 (SO4) 3 + 3H2
Let’s find the amount of aluminum substance: n = m / M = 2.7 g / 27 g / mol = 0.1 mol.
According to the reaction, 1 mol of salt is formed from 2 mol of aluminum, which means 0.1 / 2 = n (salt) / 1. Hence n (salt) = 0.1 / 2 = 0.05 mol.
Now we find the mass of the salt m = n * M = 0.05 mol * 342 g / mol = 17.1 g (M is the molar mass, determined by the periodic table).
Answer: the mass of salt is 17.1 g.