Find the mass of salt that is formed by passing carbon dioxide through 740 grams of 20% calcium hydroxide.

m (Ca (OH) 2) = 740 g.

W = 20%.

Let’s determine the mass of the resulting salt. We write down the solution.

1. First, write down the equation of reactions.

Ca (OH) 2 + CO2 = CaCO3 + H2O.

2. Find the mass of calcium hydroxide using the following formula.

W = m r.v / m r-ra * 100%.

Where W is the mass fraction.

m r.v is the mass of matter.

m solution is the mass of the solution.

m r.v = W * m solution / 100%.

m r.w = 20 * 740: 100 = 148 g of Ca (OH) 2.

Further, using the reaction equation, we find the mass of the salt obtained.

M (Ca (OH) 2) = 40 + 17 * 2 = 74 g / mol.

M (CaCO3) = 40 + 12 + 16 * 3 = 100 g / mol.

148 g Ca (OH) 2 – x g CaCO3.

74 g / mol Ca (OH) 2 – 100 g / mol CaCO3.

X = 148 * 100: 74 = 200 g / mol.

Answer: the mass of the salt obtained is 200 g / mol.



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