Find the mass of salt that is formed by passing carbon dioxide through 740 grams of 20% calcium hydroxide.
m (Ca (OH) 2) = 740 g.
W = 20%.
Let’s determine the mass of the resulting salt. We write down the solution.
1. First, write down the equation of reactions.
Ca (OH) 2 + CO2 = CaCO3 + H2O.
2. Find the mass of calcium hydroxide using the following formula.
W = m r.v / m r-ra * 100%.
Where W is the mass fraction.
m r.v is the mass of matter.
m solution is the mass of the solution.
m r.v = W * m solution / 100%.
m r.w = 20 * 740: 100 = 148 g of Ca (OH) 2.
Further, using the reaction equation, we find the mass of the salt obtained.
M (Ca (OH) 2) = 40 + 17 * 2 = 74 g / mol.
M (CaCO3) = 40 + 12 + 16 * 3 = 100 g / mol.
148 g Ca (OH) 2 – x g CaCO3.
74 g / mol Ca (OH) 2 – 100 g / mol CaCO3.
X = 148 * 100: 74 = 200 g / mol.
Answer: the mass of the salt obtained is 200 g / mol.