Find the mass of salt that is formed by the interaction of calcium oxide with 130 g of a 10% hydrochloric acid solution.

| May 5, 2021 | education

Data: mHCl (dil) is the mass of diluted hydrochloric acid taken (mHCl (dil) = 130 g); ωHCl – mass fraction of acid (ωHCl = 10% = 0.1).

Const: MHCl – molar mass of hydrochloric acid (MHCl = 36.46 g / mol); МCaCl2 – molar mass of calcium chloride (МCaCl2 = 111.08 g / mol).

1) The mass of pure acid: mHCl = mHCl (dilution) * ωHCl = 130 * 0.1 = 13 g.

2) Ur-tion of the reaction: CaCl2 (calcium chloride) + H2O (water) = CaO (calcium oxide) + 2HCl (hydrochloric acid).

3) Amount of hydrochloric acid substance: νHCl = mHCl / MHCl = 13 / 36.46 ≈ 0.357 mol.

4) Amount of the substance of the formed calcium chloride: νCaCl2 / νHCl = 1/2 and νCaCl2 = νHCl / 2 = 0.357 / 2 = 0.1785 mol.

5) Mass of calcium chloride: mCaCl2 = νCaCl2 * МCaCl2 = 0.1785 * 111.08 ≈ 19.8 g.

Answer: The mass of the formed calcium chloride is 19.8 g.



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