Find the mass of salt that is formed by the interaction of hydrochloric acid with 6.5 zinc.

Let’s find the amount of zinc.

M (Zn) = 65 g / mol.

n = 6.5 g: 65 g / mol = 0.1 mol.

Let’s compose the equation of the reaction between zinc and hydrochloric acid. Let’s find the quantitative ratios of substances.

Zn + 2HCl = ZnCl2 + H2.

According to the reaction equation, 1 mol of zinc accounts for 1 mol of salt – zinc chloride. Substances react 1: 1. The amount of the substance will be equal.

n (Zn) = n (ZnCl2) = 0.1 mol.

Find the mass of zinc chloride.

m = n × M,

M (ZnCl2) = 65 + 70 = 135 g / mol.

m = 0.1 mol × 65 g / mol = 6.5 g.

Answer: m = 6.5 g.