Find the mass of sediment that is formed by the interaction of barium nitrate with sulfuric acid in 49 grams.

univerkov | November 24, 2020 | education

Given:
m (H2SO4) = 49 grams
To find:
m (BaSO4) -?
Decision
H2SO4 + BaCl2 = 2HCl + BaSO4
M (H2SO4) = 98 g / mol
n (H2SO4) = m / M = 49/98 = 0.5 mol
n (BaSO4) = 1 * 0.5 / 1 = 0.5 mol
M (BaSO4) = 233 g / mol
m (BaSO4) = n * M = 0.5 * 233 = 116.5 grams
Answer: m (BaSO4) = 116.5 grams

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