Find the mass of silver that is formed by the interaction of 12 g of zinc with a solution containing 17 g of silver nitrate.

Zn + 2AgNO3 = Zn (NO3) 2 + 2Ag
n (AgNO3) = 0.1 mol
n (Zn) = 0.19
silver nitrate deficient
amount of silver substance = 0.1
silver mass = 0.1 * 108 = 10.8



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