Find the mass of slaked lime formed by the interaction of calcium oxide weighing 28 grams with water.
February 28, 2021 | education
| The reaction for the synthesis of slaked lime (calcium hydroxide) from unslaked lime (calcium oxide) is described by the following equation:
CaO + H2O = Ca (OH) 2;
In the course of the reaction, 1 molecule of water is attached to 1 molecule of calcium oxide.
Let’s calculate the chemical amount of a substance in 56 kilograms of calcium oxide.
To do this, divide the available weight of the oxide by the weight of one mole of oxide.
M CaO = 40 +16 = 56 grams / mol;
N CaO = 28/56 = 0.5 mol;
The same amount of calcium hydroxide will be obtained. Let’s calculate its weight.
To do this, multiply the amount of hydroxide available by the weight of one mole of hydroxide.
M Ca (OH) 2 = 40 + (16 + 1) x 2 = 74 grams / mol;
m Ca (OH) 2 = 0.5 x 74 = 37 grams;
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.