Find the mass of sodium acetate formed by the reaction of 1.61 g of sodium with acetic acid.

Let’s write down the solution sequentially:
1. Let’s compose the reaction equation:
2СН3СООН + 2Na = 2CH3COONa + H2 – substitution reaction, sodium acetate is released;
2. Let’s calculate the molar masses of substances by the formulas:
M (Na) = 22.9 g / mol;
M (CH3COONa) = 12 * 2 +1 * 3 + 16 * 2 + 22.9 = 81.9 g / mol;
3. Let’s calculate the amount of sodium moles by the formula:
Y (Na) = m / M = 1.61 / 22.9 = 2.7 mol;
4. Let’s make the proportion:
2.7 mol (Na) – X mol (CH3COONa);
-2 mol -2 mol hence, X mol (CH3COONa) = 2.7 * 2/2 = 2.7 mol;
5. Calculate the mass of sodium acetate salt by the formula:
m (CH3COONa) = Y * M = 2.7 * 81.9 = 221.13 g.
Answer: in the course of the reaction, a sodium acetate salt with a mass of 221.13 g was formed.