Find the mass of sodium carbonate that has reacted with hydrochloric acid, if 5.6 liters of carbon
| May 8, 2021 | education
Find the mass of sodium carbonate that has reacted with hydrochloric acid, if 5.6 liters of carbon monoxide (IV) have been released.
To solve this problem, we write down the reaction equation: Na2CO3 + 2HCl => 2NaCl + CO2 + H2O Find the amount of CO2 5.6 / 22, 4 = 0.25 According to the equation, the amount of carbonate and carbon monoxide coincides from here 0.25 * 106 = 26.5
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