Find the mass of sodium hydroxide, which forms upon interaction of 50 g of technical sodium containing 8%

Find the mass of sodium hydroxide, which forms upon interaction of 50 g of technical sodium containing 8% impurities with water.

Let’s execute the solution:

In accordance with the condition of the problem, we will write the data:
2Na + 2H2O = 2NaOH + H2 – OBP, hydrogen and potassium hydroxide are evolved;

Calculations:
M (Na) = 22.9 g / mol;

M (NaOH) = 39.9 g / mol;

m (Na) = 50 * (1 – 0.8) = 10 g (mass without impurities);

Y (Na) = m / M = 10 / 22.9 = 0.4 mol;

Y (NaOH) = 0.4 mol since the amount of substances is 2 mol.

Find the mass of the base:
m (NaOH) = y * M = 0.4 * 39.9 = 15.96 g

Answer: received sodium hydroxide weighing 15.96 g