Find the mass of sodium oxide, which is formed by the interaction of sodium with 4.48 liters of oxygen.

Given:
V (O2) = 4.48 L

Find:
m (Na2O) -?

1) 4Na + O2 => 2Na2O;
2) n (O2) = V (O2) / Vm = 4.48 / 22.4 = 0.2 mol;
3) n (Na2O) = n (O2) * 2 = 0.2 * 2 = 0.4 mol;
4) M (Na2O) = Mr (Na2O) = Ar (Na) * N (Na) + Ar (O) * N (O) = 23 * 2 + 16 * 1 = 62 g / mol;
5) m (Na2O) = n (Na2O) * M (Na2O) = 0.4 * 62 = 24.8 g.

Answer: The mass of Na2O is 24.8 g.