Find the mass of sulfuric acid that has reacted with sodium hydroxide weighing 2 g.

1.Let’s find the amount of sodium hydroxide substance by the formula:

n = m: M.

M (NaOH) = 23 + 16 + 1 = 40 g / mol.

n = 2 g: 40 g / mol = 0.05 mol.

2. Let’s compose the reaction equation, find the quantitative ratios of substances.

2NaOH + H2SO4 = Na2SO4 + 2H2O.

According to the reaction equation, there is 1 mol of acid per 2 mol of sodium hydroxide. Substances are in quantitative ratios of 2: 1.

The amount of sulfuric acid substance will be 2 times less than the amount of sodium hydroxide substance.

n (H2SO4) = 1 / 2n (NaOH) = 0.05: 2 = 0.025 mol.

3.Let’s find the mass of H2SO4,

m = n M.

M (H2SO4) = 98 g / mol.

m = 0.025 mol × 98 g / mol = 2.45 g.

Answer: m = 2.45 g.