Find the mass of the formed salt if 5.6 grams of potassium hydroxide has reacted with sulfuric acid.

The equation of the ongoing reaction: H2SO4 + 2KOH = K2SO4 + 2H2O.
1) Find the molar mass of sulfuric acid according to the periodic table: 1 * 2 + 32 + 4 * 16 = 98.
2) Find the amount of sulfuric acid substance. To do this, divide the mass of the acid by its molar mass: 5.6 / 98 = 0.06 mol.
3) According to the reaction equation, there is one potassium sulfate salt for one mole of sulfuric acid. Thus, the amount of the potassium sulfate substance is 0.06 mol.
4) Molar mass of potassium sulfate: 39 * 2 + 32 + 16 * 4 = 174.
5) Mass of potassium sulfate: 174 * 0.06 = 10.44 g – answer.