Find the mass of the precipitate in the interaction of 34 g of silver nitrate + ferric chloride (2).

univerkov | March 15, 2021 | education

2AgNO3 + FeCl2 = 2AgCl + Fe (NO3) 2.
1) Find the molar mass of silver nitrate: 108 + 14 + 16 * 3 = 170.
2) Find the amount of silver nitrate substance. To do this, divide the mass of nitrate by its molar mass: 34/170 = 0.2 mol.
3) According to the reaction equation, for two moles of silver nitrate, there are two moles of silver chloride (precipitate). This means that the amount of silver chloride substance is 0.2 mol.
4) Find the molar mass of silver chloride: 108 + 35.5 = 143.5.
5) Find the mass of the sediment: 143.5 * 0.2 = 28.7 g – the answer.

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