Find the mass of the precipitate obtained by the interaction of 25 g Cu (So4) and 39 g K (OH)

CuSO4 + 2KOH = Cu (OH) 2 + K2SO4.
Progress in solving the problem:
1) Calculation of the molar mass of copper sulfate.
2) Calculation of the amount of copper sulfate substance.
3) Calculation of the molar mass of potassium hydroxide.
4) Calculation of the amount of potassium hydroxide substance.
5) Definition of excess-deficiency.
6) Determination of the amount of copper hydroxide substance.
7) Calculation of the sediment mass.
Decision:
1) 64 + 32 + 64 = 160.
2) 25/160 = 0.16 mol.
3) 39 + 1 + 16 = 56.
4) 34/56 = 0.6 mol.
5) Lack of potassium hydroxide. We calculate on it.
6) 0.6 mol.
7) 0.6 * (65 + 32 + 2) = 59.4 – answer.