Find the mass of the precipitate that will result from the interaction of barium chloride with sulfuric acid weighing 19.6.
February 9, 2021 | education
| Barium chloride reacts with sulfuric acid. In this case, a water-insoluble barium sulfate salt is formed, which turns into an insoluble precipitate. The reaction is described by the following chemical reaction equation.
BaCl2 + H2SO4 = BaSO4 + 2HCl;
Barium chloride reacts with sulfuric acid in equal molar amounts. This synthesizes the same amount of insoluble barium sulfate.
Let’s calculate the chemical amount of sulfuric acid.
M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; N H2SO4 = 19.6 / 98 = 0.2 mol;
The same amount of barium sulfate will be synthesized.
Let’s calculate its weight.
M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; m BaSO4 = 0.2 x 233 = 46.6 grams;
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