Find the mass of the salt obtained by the interaction of 2.4 g of magnesium with a solution of hydrochloric acid.

1. Let’s write down the reaction equation:

Mg + 2HCl = MgCl2 + H2.

2. Find the amount of magnesium:

n (Mg) = m (Mg) / M (Mg) = 2.4 g / 24 g / mol = 0.1 mol.

3. According to the reaction equation, we find the amount of magnesium chloride, and then its mass:

n (MgCl2) = n (Mg) = 0.1 mol.

m (MgCl2) = n (MgCl2) * M (MgCl2) = 0.1 mol * 95 g / mol = 9.5 g.

Answer: m (MgCl2) = 9.5 g.