Find the mass of the salt that is formed by the interaction of 196 g of sulfuric acid with barium hydroxide.

Barium hydroxide reacts with sulfuric acid. This results in the formation of water-insoluble barium sulfate, which precipitates. This reaction is described by the following chemical equation.
Ba (OH) 2 + H2SO4 = BaSO4 + 2H2O;
Barium hydroxide reacts with sulfuric acid in equivalent molar amounts. In this case, the same amount of insoluble salt passes into an insoluble precipitate.
Let’s determine the chemical amount of sulfuric acid.
M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; N H2SO4 = 196/98 = 2 mol;
Barium sulfate will be synthesized in the same molar amount.
Let’s find its weight.
M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; m BaSO4 = 2 x 233 = 466 grams.