Find the mass of the salt that is formed by the interaction of 35.5 g of hydrochloric acid with magnesium hydroxide.

univerkov | November 22, 2020 | education

Mg (OH) 2 + 2HCl → MgCl2 + 2H2O
n (HCl) = m / M = 35.5g / 36.5 g / mol = 0.9 mol
n (MgCl2) = 0.9 / 2 = 0.45 mol
m (MgCl2) = n * M = 0.45 mol * 95 g / mol = 42.75 g
Answer: m (MgCl2) = 42.75 g

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