Find the mass of the salt that was obtained as a result of the interaction of nitric acid with 300 mg of iron oxide (3).

1. The interaction of nitric acid with iron oxide is described by the reaction equation:

6HNO3 + Fe2O3 = 2Fe (NO3) 3 + 3H2O;

2.Calculate the chemical amount of iron oxide:

n (Fe2O3) = m (Fe2O3): M (Fe2O3);

M (Fe2O3) = 2 * 56 + 3 * 16 = 160 g / mol;

n (Fe2O3) = 300: 160 = 1.875 mmol;

3.determine the amount of iron nitrate obtained (3):

n (Fe (NO3) 3) = n (Fe2O3) * 2 = 1.875 * 2 = 3.75 mmol;

4. find the mass of salt:

m (Fe (NO3) 3) = n (Fe (NO3) 3) * M (Fe (NO3) 3);

M (Fe (NO3) 3) = 56 + 3 * 14 + 9 * 16 = 242 g / mol;

m (Fe (NO3) 3) = 3.75 * 242 = 907.5 mg.

Answer: 907.5 mg.