Find the mass of the sediment that forms when 90 g of a 5% solution of ferric chloride with the required

Find the mass of the sediment that forms when 90 g of a 5% solution of ferric chloride with the required amount of sodium hydroxide

FeCl3 + 3NaOH = 3NaCl + Fe (OH) 3.
m FeCl3 = 90 * (5% / 100%) = 4.5 g, N = 4.5 / 162 = 0.02778 mol.
m Fe (OH) 3 = 0.02778 * 107 = 2.97 g.



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