Find the mass of water contained in 750 g of copper sulfate (CuSO4 * 5H2O)

w (CuSO4) in crystalline hydrate = 160 \ (160 + 18 * 5) = 0.64
m (CuSO4) = w * m (CuSO4 * 5H2O) = 750 * 0.64 = 480 g
m (H2O) = 750-480 = 270 g
Answer: m (H2O) = 270 g



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