Find the mass of water from 4.48 liters of hydrogen n y when interacting with oxygen.
| August 3, 2021 | education
1. Let’s write down the reaction equation:
2H2 + O2 = 2H2O.
2. Find the amount of hydrogen (Vm – molar volume, constant equal to 22.4 l / mol):
n (H2) = V (H2) / Vm = 4.48 L / 22.4 L / mol = 0.2 mol.
3. Using the reaction equation, we find the amount and then the mass of water:
n (H2O) = n (H2) = 0.2 mol.
m (H2O) = n (H2O) * M (H2O) = 0.2 mol * 18 g / mol = 3.6 g.
Answer: m (H2O) = 3.6 g.
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