Find the mass of water required for the complete interaction of 11.2 g of calcium with water.
August 28, 2021 | education|
1. Let’s compose the equation of interaction of calcium with water:
Ca + 2H2O = Ca (OH) 2 + H2 ↑.
2. Find the chemical amount of calcium:
n (Ca) = m (Ca): M (Ca) = 11.2: 40 = 0.28 mol.
3. Determine the amount of water:
n (H2O) = n (Ca) * 2 = 0.28 * 2 = 0.56 mol.
4. Let’s calculate the mass of water required for the reaction:
m (H2O) = n (H2O) * M (H2O) = 0.56 * 18 = 10.08 g.
Answer: 10.08 g.
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