Find the mass of water that is formed by combining 44.8 liters of hydrogen with oxygen. (formula: 2H2 + O2 = 2H2O)

Let’s implement the solution:

According to the condition of the problem, we write:
2H2 + O2 = 2H2O – compounds, water is released.

Proportion:
1 mole of gas at normal level – 22.4 liters;

X mol (H2) -44.8 L from here, X mol (H2) = 1 * 44.8 / 22.4 = 2 mol;

Y (H2O) = 2 mol since the amount of substances is equal to 2 mol.

Find the mass of the product:
m (H2O) = 2 * 18 = 36 g

Answer: received water weighing 36 g