Let’s implement the solution:
According to the condition of the problem, we write:
2H2 + O2 = 2H2O – compounds, water is released.
1 mole of gas at normal level – 22.4 liters;
X mol (H2) -44.8 L from here, X mol (H2) = 1 * 44.8 / 22.4 = 2 mol;
Y (H2O) = 2 mol since the amount of substances is equal to 2 mol.
Find the mass of the product:
m (H2O) = 2 * 18 = 36 g
Answer: received water weighing 36 g
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