Find the mass of water that is formed during the decomposition of 148 g of Ca hydroxide

1. Let’s write down the reaction equation:

Ca (OH) 2 = CaO + H2O.

2. Find the amount of reacted calcium hydroxide:

n (Ca (OH) 2) = m (Ca (OH) 2) / M (Ca (OH) 2) = 148 g / 74 g / mol = 2 mol.

3. According to the reaction equation, we find the amount and then the mass of the released water:

n (H2O) = n (Ca (OH) 2) = 2 mol.

m (H2O) = n (H2O) * M (H2O) = 2 mol * 18 g / mol = 36 g.

Answer: m (H2O) = 36 g.



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