Find the mass of water that was obtained as a result of the interaction of hydrogen with oxygen

Find the mass of water that was obtained as a result of the interaction of hydrogen with oxygen, if 48 g of oxygen were consumed.

1.Let’s find the amount of substance O by the formula:

n = m: M.

M (O2) = 32 g / mol.

n = 48 g: 32 g / mol = 1.5 mol.

2. Let’s compose the reaction equation, find the quantitative ratios of substances.

2H2 + O2 = 2H2O.

According to the reaction equation, there is 2 mol of H2O per 1 mole of O2. The substances are in quantitative ratios of 1: 2.

The amount of substance Н2О will be 2 times more than О2.

n (H2O) = 2 n (O2) = 1.5 × 2 = 3 mol.

3.Let’s find the mass of H2O.

m = n × M.

M (H2O) = 18 g / mol.

m = 18 g / mol × 3 mol = 54 g.

Answer: 54 g.