Find the mass of water that will be obtained if 8 grams of oxygen has entered into a reaction with hydrogen.

univerkov | November 23, 2020 | education

Given: m (O2) = 8g
m (H20) -?
Solution 2H20 + O2 -> 2H2Ob n = m / M n (H20) = 8g / 32g = 0.25 mol n (H20) 2 times> n (O2) n (H2O) = 0.25 mol × 2 = 0 , 5 mol m = n × M m (H2O) = 0.5 mol × 18 g / mol = 9 g
Answer: m (H2O) = 9g.

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