Find the mass, volume and amount of the substance carbon dioxide, which was formed by the interaction

Find the mass, volume and amount of the substance carbon dioxide, which was formed by the interaction of calcium carbonate with a mass of 100 g and hydrochloric acid.

CaCO3 + 2HCl = CaCl2 + CO2 + H2O
amount of calcium carbonate substance = 100/100 = 1 mol
hence
n (co2) = 1 mol
m (co2) = 1 * 44 = 44 g
v (co2) = 22.4 * 1 = 22.4 liters



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