Find the maximum mass of bromine water with a mass fraction of bromine

Find the maximum mass of bromine water with a mass fraction of bromine equal to 2%, which can be discolored by 1.12 l of butadiene-1,3

Given:
ω (Br2) = 2%
V (C4H6) = 1.12 L

To find:
m solution (Br2) -?

1) Write the reaction equation:
2Br2 + C4H6 => C4H6Br4;
2) Calculate the amount of substance C4H6:
n (C4H6) = V (C4H6) / Vm = 1.12 / 22.4 = 0.05 mol;
3) Determine the amount of substance Br2:
n (Br2) = n (C4H6) * 2 = 0.05 * 2 = 0.1 mol;
4) Calculate the mass of Br2:
m (Br2) = n (Br2) * M (Br2) = 0.1 * 160 = 16 g;
5) Calculate the mass of bromine water:
m solution (Br2) = m (Br2) * 100% / ω (Br2) = 16 * 100% / 2% = 800 g.

Answer: The mass of bromine water is 800 g.