Find the minimum point of the function y = x3-108x + 19.

First, we find the derivative of this function:
y ‘= 3x ^ 2-108
Then we equate the derivative to zero:
3x ^ 2-108 = 0
3x ^ 2 = 108
x ^ 2 = 36
x1 = 6 and x2 = -6
We draw the X-axis and put down points 6 and -6. We determine the signs in the intervals by selecting any number from the interval and substituting it into the derivative.
__ + __- 6 ___-___ 6 __ + __

The minimum point will be at the transition from minus to plus, that is, the minimum point is 6