Find the molecular formula of an alkadiene with a molar mass of 94, build the formulas for all isomers.

Let’s write down the condition of the problem:
СnH2n – 2 – general formula of alkadienes;
M (CxHy) = 94 g / mol;
Find: molecular formula CxHy;
Make up isomers:
Decision:
1. Find the value – n, applying the general formula:
CnH2n – 2 = 94 g / mol;
12n + 2 – 2 = 94;
12n = 90;
N = 7.5;
2. Molecular formula of alkadiene C7H12 (heptadiene).
3. H2C = CH – CH = CH – CH2 – CH2 – CH3 – heptadiene -1.3;

4. Formulas of isomers: Н2С = СН – СН2 – СН = СН – СН2 – СН3 – hexadiene -1.4;

H3C – CH = CH – CH2 – CH = CH – CH3 – hexadiene -2.5;
H3C – C – (CH3) – CH = CH – CH = CH2 – 2 – methylhexadiene – 3.5;
H2C = C – (C2H5) – CH2 – CH = CH2 – 2 – ethyl pentadiene – 1.4