m (CaSiO3) = 232 g
N (CaSiO3) -?
1) M (CaSiO3) = Mr (CaSiO3) = Ar (Ca) * N (Ca) + Ar (Si) * N (Si) + Ar (O) * N (O) = 40 * 1 + 28 * 1 + 16 * 3 = 116 g / mol;
2) n (CaSiO3) = m (CaSiO3) / M (CaSiO3) = 232/116 = 2 mol;
3) N (CaSiO3) = n (CaSiO3) * NA = 2 * 6.02 * 10 ^ 23 = 1.204 * 10 ^ 24.
Answer: The number of CaSiO3 molecules is 1.204 * 10 ^ 24.
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