Find the number of dissociated particles if it is known that 3 mol of barium chloride substance

Find the number of dissociated particles if it is known that 3 mol of barium chloride substance has been dissolved. The degree of electrolytic dissociation is 0.73.

Given: Solution: BaC12 = Ba (2 +) + 2Cl (1-)
a = 0.73 N (BaCl2) dissociated = n * 0.73 * Na =
n (BaCl2) = 3 mol = 3 * 0.73 * 6.02 * 10 ^ 23 = 13.1838 * 10 ^ 23 molecules
nВа (2 +) = 3 * 0.73 = 2.19 mol
N (Ba (2 +)) = n * Na = 2.19 * 6.02 * 10 ^ 23 =
= 13.1838 * 10 ^ 23 ions
n (Cl (1 -)) = 2 * 3 * 0.73 = 4.38 mol
N (Cl (1 -)) = n * Na = 4.38 * 6.02 * 10 ^ 23 = 26.3676 * 10 ^ 23 ions