Find the outer angle CBD in the triangle ABC AC = BC, angle C = 116 degrees.

In triangle ABC, sides AC = BC, angle C = 116 °.

Find the outer corner of the CBD.

Since the sides of the triangle are equal, it means that the triangle is isosceles.

In an isosceles triangle, 2 angles are equal.

Angle A = Angle B.

All angles add up to 180.

180 – 116 = 64.

Since the sum of the two angles A and B is 64, then:

Angle B = 64/2 = 32 °.

Then, the outer angle CBD is 180 – the angle B = 180 – 32 = 148 °.

This means that the external angle CBD is 148 °.