Find the outer CBD in the triangle ABC AC = BC angle C = 50.

In a triangle abc, the sides ac = bc are equal. It is known that the angle c = 50 °.

Let’s find the external CBD.

Decision.

The triangle is isosceles because the sides of the triangle are equal. So 2 angles are also equal, that is, angle a = angle b.

Angle a + angle b + angle c = 180 °;

Angle b + angle b + angle c = 180 °;

2 * angle b + angle c = 180 °;

2 * angle at + 50 ° = 180 °;

2 * angle b = 180 ° – 50 °;

2 * angle в = 130 °;

Angle B = 130 ° / 2;

Angle b = 75 °;

Then, angle (CBD) = 180 ° – 75 ° = 105 °;

Hence, the angle (CBD) = 105 °.

Answer: Angle (CBD) = 105 °.