Find the outer corner of a convex octagon if its inner corners are equal.

Bo first, you should determine what the inner corner of the octagon is equal to. Since in the proposed task we are talking about a regular octagon (y of which all sides and internal angles are equal, and the latter is directly indicated in the condition of the task), then the value of its internal angle is found by the formula:

a = (180o * (n – 2)) / n = (180o * (8 – 2)) / 8 = (180o * 6) / 8 = 135o.

Therefore, we find the value of the external angle, which is adjacent to the internal one:

b = 180o – 135o = 45o.

Answer: outside angle = 45o.