Find the perimeter and area of a rectangle, one side of which is 56 cm and the other 4 times smaller.

Given:
Length – 56 cm.
Width – 4 times less.
Find: perimeter and area
To find the width of the rectangle, you need to divide the number 56 by 4. (Since the width is 4 times less than the length). We get:
56: 4 = 14 cm – width.
The perimeter is the sum of all sides. The rectangle has two widths and two lengths. So you need to multiply each side by 2. We get:
14 * 2 + 56 * 2 = 28 + 112 = 140 cm – the perimeter of the rectangle.
Area is the product of length and width. We get:
14 * 56 = 784 cm² – the area of the rectangle.
Answer: 140 cm – perimeter; 784 cm² – area.