Find the perimeter and area of a rectangle that is 7.7 m long and 4 times less wide.

To solve this problem, recall the formula for the area of a rectangle. The area of the rectangle is equal to the product of the length and the width. S = a * b, where a is the length and b is the width. The perimeter of a rectangle is the sum of the lengths of all its sides. Since in a rectangle the opposite sides are equal, then P = 2 * (a + b), where a is the length, b is the width. Let’s calculate the width of the rectangle.
7.7 * 4 = 30.8 meters.
Let’s calculate the area.
S = 30.8 * 7.7 = 237.16 m ^ 2.
P = 2 * (30.8 + 7.7) = 2 * 38.5 = 77 meters.
Answer: 237.16 m ^ 2; 77 m.

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