Find the perimeter and area of a rectangular section 25 m wide and 10 m longer than width.

Let’s find the length of this rectangular section.
According to the condition of the problem, the width of this rectangular section is 25 m, and the length of this section is 10 m greater than its width, therefore, the length of this section is:
25 + 10 = 35 m.
We find the perimeter P of a given rectangular section as the doubled sum of the length and width of this section:
p = 2 * (35 + 25) = 2 * 60 = 120 m.
Let us find the area S of a given rectangular section as the product of the length and width of this section:
S = 35 * 25 = 875 m².
Answer: the perimeter of this rectangular section is 120 m, the area of ​​this rectangular section is 875 m2



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