Find the perimeter and area of the rectangle if one side of it is even 15/6 meters

Find the perimeter and area of the rectangle if one side of it is even 15/6 meters and the other is 31/42 meters larger than it.

1. Determine the size of the second side of the rectangle:

15/6 + 31/42 = 105/42 + 31/42 = 136/42 m;

2. Determine the perimeter of the rectangle:

(15/6 + 136/42) x 2 = (105/42 + 136/42) x 2 = (241/42) x 2 = 241/21 = 11.10 / 21 m;

3. Determine the area of \ u200b \ u200bthe rectangle:

15/6 x 136/42 = 15/6 x 68/21 = 1020/126 = 170/21 = 8.2 / 21 m².

Answer: The perimeter of the rectangle is 11.10 / 21 meters, the area of the rectangle is 8.2 / 21 square meters.