Find the perimeter of a rectangle if its area is 98 cm, and one of its sides is twice as large as the other.

A rectangle is a quadrangle in which opposite sides are equal and all corners are right:

AB = CD;

BC = AD.

The area of a rectangle is the product of its length and width:

S = a * b.

Since the length of the rectangle is twice its width, and the area is 98 cm2, then we express:

x is the width of the rectangle;

2x – its length;

x * 2x = 98;

2×2 = 98;

x2 = 98/2 = 49;

x = √49 = 7;

AB = CD = 7 cm;

BC = AD = 2 * 7 = 14 cm.

The perimeter of a rectangle is the sum of all its sides:

P = AB + BC + CD + AD;

P = 7 + 14 + 7 + 14 = 42 cm.

Answer: The perimeter of the rectangle is 42 cm.