Find the perimeter of a rectangle that is 12 inches wide and 5 times longer.

Let’s find what the length of this rectangle is equal to.

According to the condition of the problem, the width of this rectangle is 12 dm, and the length of this rectangle is 5 times its width, therefore, the length of this rectangle is:

12 * 5 = 60 dm.

Find the perimeter P of a given rectangle as the doubled sum of the length and width of this rectangle:

P = 2 * (60 + 12) = 2 * 72 = 144 dm.

Answer: the perimeter of this rectangle is 144 dm.



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