Find the perimeter of a rectangular triangle in which the height drawn from the vertex
Find the perimeter of a rectangular triangle in which the height drawn from the vertex of the right angle divides the hypotenuse into segments of 9 and 16 cm.
Since CH is the height of a right-angled triangle drawn to the hypotenuse from the apex of the right angle, then CH ^ 2 = AH * BH = 16 * 9 = 144.
CH = 12 cm.
In a right-angled triangle BCH, according to the Pythagorean theorem, BC ^ 2 = CH^2 + BH^2 = 144 + 81 = 225.
BC = 15 cm.
The length of the hypotenuse AB = AH + BH = 16 + 9 = 25 cm.
In a right-angled triangle ABC, according to the Pythagorean theorem, AC ^ 2 = AB ^ 2 – BC ^ 2 = 625 – 225 = 400.
AC = 20 cm.
Let’s define the perimeter of the triangle ABC.
Ravs = AB + BC + AC = 25 + 15 + 20 = 60 cm.
Answer: The perimeter of the triangle is 60 cm.