Find the perimeter of a rhombus whose area is 9.6 m squared, and one of the diagonals is 3.2 m.
| November 22, 2020 | education
The second diagonal will be equal to:
D2 = 2S: D1, D2 = 19.2
By the property of the diagonals of a rhombus: the diagonals intersect at right angles and the intersection point is halved.
By the Pythagorean theorem:
a ^ 2 = 1 / 2d1 ^ 2 + 1 / 2d2 ^ 2
a = 6.2
Means:
P = 4 * 6.2 = 24.8
Answer: 24.8
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