Find the perimeter of rectangles with a length of 14 inches, a width of 9 inches, a length of 24 cm

Find the perimeter of rectangles with a length of 14 inches, a width of 9 inches, a length of 24 cm, a width of 15 cm shorter, a width of 21 mm, and a length of 4 mm longer.

Given:

length – 14 dm;

width – 9 dm;

P =? dm.

The perimeter is calculated by the formula: P = 2 * (a + b) – where, a is the length, b is the width.

P = 2 * (a + b) = 2 * (14 + 9) = 2 * 23 = 46 (dm).

Answer: 240 dm. the perimeter of the rectangle.

Given:

length – 14 dm;

width – width 15 cm shorter;

P =? dm.

Let’s find the width of the rectangle:

1 dm = 10 cm; 14 dm = 140 cm

14 dm – 15 cm = 140 – 15 = 125 (cm)

The perimeter is calculated by the formula: P = 2 * (a + b) – where, a is the length, b is the width.

P = 2 * (a + b) = 2 * (140 + 125) = 2 * 265 = 530 (cm).

Answer: 530 cm. Perimeter of the rectangle.

Given:

length – 4 mm longer;

width – 21 mm;

P =? dm.

Let’s find the length of the rectangle:

1) 21 – 4 = 17 (mm)

The perimeter is calculated by the formula: P = 2 * (a + b) – where, a is the length, b is the width.

P = 2 * (a + b) = 2 * (21 + 17) = 2 * 38 = 76 (mm).

Answer: 76 mm. the perimeter of the rectangle.