Find the perimeter of the parallelogram if the bisector of one of its corners divides the side by 10 and 14.

Because AE is the bisector, then angle BAE = angle DAE, since ABСD is a parallelogram, then the angle BEA = angle EAD (as in a cross at the secant EA) => angle BAE = angle BEA. ABE is isosceles, because the angles at the base are => BE = BA = 10 cm. BC = AD = 10 + 14 = 24 cm Perimeter = 24 + 24 + 10 + 10 = 68 cm.



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